tolong dong bantuinnn
jangan jawab asal ya...
jangan jawab asal ya...
Jawab:
limit substitusi nilai x
1)
[tex]\sf lim_{x\to ~ -2} \dfrac{x^5 + 3x^2 - 1}{(x - 2)(x^2 - 2x - 1)}[/tex]
subsitusikan nilai x = - 2
[tex]\sf lim_{x\to ~ -2} \dfrac{(-2)^5 + 3(-2)^2 - 1}{(-2 - 2)((-2)^2 - 2(-2) - 1)}[/tex]
[tex]\sf lim_{x\to ~ -2} \dfrac{-32+ 12 - 1}{-4(7)}= \dfrac{-21}{-28} = \dfrac{3}{4}[/tex]
2) lim (x -> 1 ) (x² - 3)⁵
substitusi nilai x =1
= (1² - 3)⁵
= (1- 3)⁵
= (-2)⁵
= - 32
[answer.2.content]
